Please use this identifier to cite or link to this item: https://open.uns.ac.rs/handle/123456789/13566
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dc.contributor.authorTreml M.en
dc.date.accessioned2020-03-03T14:52:50Z-
dc.date.available2020-03-03T14:52:50Z-
dc.date.issued1999-03-28en
dc.identifier.issn0012365Xen
dc.identifier.urihttps://open.uns.ac.rs/handle/123456789/13566-
dc.description.abstractResearch problem 231, Discrete Mathematics 140 (1995) says: Let A be a set of 2k, k ≥ 2, distinct positive integers. It is desired to partition A into two subsets A0 and A1 each with cardinality k so that the sum of any k - 1 elements of Ai is not an element of Ai+1, i = 0, 1 mod 2. It is not possible to find such a partition when A is {1,3,4,5,6,7} or any of {1,2,3,4,5,x}, x ≥ 7. Can it be done in all other cases? We show that the answer is affirmative for k ≥ 3 with some exceptions for k = 3. © 1999 Elsevier Science B.V. All rights reserved.en
dc.relation.ispartofDiscrete Mathematicsen
dc.titleSome partitions of positive integersen
dc.typeJournal/Magazine Articleen
dc.identifier.doi10.1016/S0012-365X(98)00307-0en
dc.identifier.scopus2-s2.0-0041706611en
dc.identifier.urlhttps://api.elsevier.com/content/abstract/scopus_id/0041706611en
dc.relation.lastpage271en
dc.relation.firstpage267en
dc.relation.issue1-3en
dc.relation.volume199en
item.grantfulltextnone-
item.fulltextNo Fulltext-
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